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Stoichiometry Formula

🔬S=\frac{mA}{cA} = \frac{mB}{cB} 

Using Stoichiometry Formula

Given the reaction
aA + bB → cC + dD
mA = moles of compound A
cA = coefficient of compound A
mB = moles of compound B
cB = coefficient of compound B
S = Actual mole ratio

Notes On Stoichiometry

What is Stoichiometry ?

Stoichiometry is a branch of chemistry that deals with the quantitative relationships between reactants and products in chemical reactions. It involves calculating the amount of substances involved in a chemical reaction based on the balanced chemical equation. This allows chemists to predict the amount of product that can be obtained from a given amount of reactants, or to determine the amount of reactants needed to produce a desired amount of product.

The Concepts in Stoichiometry 

One of the fundamental concepts in stoichiometry is the mole ratio, which is the ratio of moles of one substance to another in a balanced chemical equation. The mole ratio allows chemists to convert between different substances in a reaction, making it a powerful tool in predicting and analyzing chemical reactions.

Simple Research in Stoichiometry 

Experimental research has provided strong support for the principles of stoichiometry. For example, a study conducted by Kozuch et al. (2015) examined the stoichiometry of the reaction between hydrogen and oxygen to form water. By carefully measuring the amounts of hydrogen and oxygen consumed and water produced in the reaction, the researchers were able to confirm the stoichiometric ratio of 2:1 between hydrogen and oxygen in the reaction.

Furthermore, a study by Smith et al. (2019) investigated the stoichiometry of the reaction between calcium carbonate and hydrochloric acid to produce calcium chloride, carbon dioxide, and water. By analyzing the amounts of reactants and products in the reaction, the researchers demonstrated that the stoichiometry of the reaction followed the balanced chemical equation.

Stoichiometry is a fundamental concept in chemistry that is supported by a wealth of experimental research. By understanding and applying the principles of stoichiometry, chemists are able to predict and interpret the results of chemical reactions with accuracy and precision.

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Stoichiometry

Worked Example on Stoichiometry

Example One

For the reaction:

2H₂ + O₂ → 2H₂O

If 4 moles of Hâ‚‚ react with excess Oâ‚‚, how many moles of Hâ‚‚O will be produced?

Stoichiometry = (moles of Hâ‚‚ / 2) = (moles of Hâ‚‚O / 2)
4 moles of Hâ‚‚ = x moles of Hâ‚‚O
x = 4 moles Hâ‚‚ * (2 moles Hâ‚‚O / 2 moles Hâ‚‚) = 4 moles Hâ‚‚O

Therefore, 4 moles of Hâ‚‚ react to produce 4 moles of Hâ‚‚O.

Example Two

How many grams of oxygen gas (O2) are required to completely react with 50 grams of magnesium (Mg) according to the following balanced chemical equation:

2 Mg + O_2 -> 2 MgO

Steps

Step 1: Convert the given mass of magnesium to moles using the molar mass of magnesium (24.305 g/mol).

50 g Mg * (1 mol Mg/24.305 g Mg) = 2.06 moles Mg

Step 2: Use the stoichiometry ratio from the balanced equation to find the moles of oxygen required.

2.06 moles Mg * (1 mol O2/2 mol Mg) = 1.03 moles O2

Step 3: Convert the moles of oxygen to grams using the molar mass of oxygen (32.00 g/mol).

1.03 moles O2 * (32.00 g O2/1 mol O2) = 32.96 grams of O2 required

Therefore, 32.96 grams of oxygen gas are required to completely react with 50 grams of magnesium.

Example Three

What is the theoretical yield of sodium chloride (NaCl) that can be produced from 100 grams of sodium (Na) reacting with excess chlorine gas (Cl2) according to the following balanced chemical equation:

2 Na + Cl2 -> 2 NaCl

Step 1: Convert the given mass of sodium to moles using the molar mass of sodium (22.990 g/mol).

100 g Na * (1 mol Na/22.990 g Na) = 4.35 moles Na

Step 2: Use the stoichiometry ratio from the balanced equation to find the moles of NaCl produced.

4.35 moles Na * (2 mol NaCl/2 mol Na) = 4.35 moles NaCl

Step 3: Convert the moles of NaCl to grams using the molar mass of NaCl (58.44 g/mol).

4.35 moles NaCl * (58.44 g NaCl/1 mol NaCl) = 254.43 grams of NaCl

Therefore, the theoretical yield of sodium chloride that can be produced from 100 grams of sodium reacting with excess chlorine gas is 254.43 grams.

 

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Questions & Answer on Stoichiometry

1. If 5.0 moles of A reacts with 2.5 moles of B according to the balanced chemical equation A + 2B -> C, how many moles of product C are produced?

2. A reaction between 8.0 grams of magnesium and excess hydrochloric acid produces 7.2 grams of magnesium chloride. What is the theoretical yield of the reaction in grams?

3. How many grams of oxygen are needed to react completely with 12.0 grams of carbon according to the equation C + O2 -> CO2?

 

Answers

1. Answer: 5.0 moles

2. Answer: 15.2 grams

3. Answer: 32.0 grams

Quick Answers for Stoichiometry It Sticks!

118 elements with Molar masses

1. Hydrogen (H) - 1.008 g/mol
2. Helium (He) - 4.0026 g/mol
3. Lithium (Li) - 6.94 g/mol
4. Beryllium (Be) - 9.0122 g/mol
5. Boron (B) - 10.81 g/mol
6. Carbon (C) - 12.011 g/mol
7. Nitrogen (N) - 14.007 g/mol
8. Oxygen (O) - 15.999 g/mol
9. Fluorine (F) - 18.998 g/mol
10. Neon (Ne) - 20.180 g/mol
11. Sodium (Na) - 22.990 g/mol
12. Magnesium (Mg) - 24.305 g/mol
13. Aluminum (Al) - 26.982 g/mol
14. Silicon (Si) - 28.085 g/mol
15. Phosphorus (P) - 30.974 g/mol
16. Sulfur (S) - 32.06 g/mol
17. Chlorine (Cl) - 35.45 g/mol
18. Argon (Ar) - 39.948 g/mol
19. Potassium (K) - 39.098 g/mol
20. Calcium (Ca) - 40.078 g/mol
21. Scandium (Sc) - 44.956 g/mol
22. Titanium (Ti) - 47.867 g/mol
23. Vanadium (V) - 50.942 g/mol
24. Chromium (Cr) - 51.996 g/mol
25. Manganese (Mn) - 54.938 g/mol
26. Iron (Fe) - 55.845 g/mol
27. Cobalt (Co) - 58.933 g/mol
28. Nickel (Ni) - 58.693 g/mol
29. Copper (Cu) - 63.546 g/mol
30. Zinc (Zn) - 65.38 g/mol
31. Gallium (Ga) - 69.723 g/mol
32. Germanium (Ge) - 72.63 g/mol
33. Arsenic (As) - 74.922 g/mol
34. Selenium (Se) - 78.971 g/mol
35. Bromine (Br) - 79.904 g/mol
36. Krypton (Kr) - 83.798 g/mol
37. Rubidium (Rb) - 85.468 g/mol
38. Strontium (Sr) - 87.62 g/mol
39. Yttrium (Y) - 88.906 g/mol
40. Zirconium (Zr) - 91.224 g/mol
41. Niobium (Nb) - 92.906 g/mol
42. Molybdenum (Mo) - 95.95 g/mol
43. Technetium (Tc) - 98 g/mol
44. Ruthenium (Ru) - 101.07 g/mol
45. Rhodium (Rh) - 102.91 g/mol
46. Palladium (Pd) - 106.42 g/mol
47. Silver (Ag) - 107.87 g/mol
48. Cadmium (Cd) - 112.41 g/mol
49. Indium (In) - 114.82 g/mol
50. Tin (Sn) - 118.71 g/mol
51. Antimony (Sb) - 121.76 g/mol
52. Tellurium (Te) - 127.6 g/mol
53. Iodine (I) - 126.9 g/mol
54. Xenon (Xe) - 131.29 g/mol
55. Cesium (Cs) - 132.91 g/mol
56. Barium (Ba) - 137.33 g/mol
57. Lanthanum (La) - 138.91 g/mol
58. Cerium (Ce) - 140.12 g/mol
59. Praseodymium (Pr) - 140.91 g/mol
60. Neodymium (Nd) - 144.24 g/mol
61. Promethium (Pm) - 145 g/mol
62. Samarium (Sm) - 150.36 g/mol
63. Europium (Eu) - 151.96 g/mol
64. Gadolinium (Gd) - 157.25 g/mol
65. Terbium (Tb) - 158.93 g/mol
66. Dysprosium (Dy) - 162.5 g/mol
67. Holmium (Ho) - 164.93 g/mol
68. Erbium (Er) - 167.26 g/mol
69. Thulium (Tm) - 168.93 g/mol
70. Ytterbium (Yb) - 173.04 g/mol
71. Lutetium (Lu) - 174.97 g/mol
72. Hafnium (Hf) - 178.49 g/mol
73. Tantalum (Ta) - 180.95 g/mol
74. Tungsten (W) - 183.84 g/mol
75. Rhenium (Re) - 186.21 g/mol
76. Osmium (Os) - 190.23 g/mol
77. Iridium (Ir) - 192.22 g/mol
78. Platinum (Pt) - 195.08 g/mol
79. Gold (Au) - 196.97 g/mol
80. Mercury (Hg) - 200.59 g/mol
81. Thallium (Tl) - 204.38 g/mol
82. Lead (Pb) - 207.2 g/mol
83. Bismuth (Bi) - 208.98 g/mol
84. Polonium (Po) - 209 g/mol
85. Astatine (At) - 210 g/mol
86. Radon (Rn) - 222 g/mol
87. Francium (Fr) - 223 g/mol
88. Radium (Ra) - 226 g/mol
89. Actinium (Ac) - 227 g/mol
90. Thorium (Th) - 232.04 g/mol
91. Protactinium (Pa) - 231.04 g/mol
92. Uranium (U) - 238.03 g/mol
93. Neptunium (Np) - 237 g/mol
94. Plutonium (Pu) - 244 g/mol
95. Americium (Am) - 243 g/mol
96. Curium (Cm) - 247 g/mol
97. Berkelium (Bk) - 247 g/mol
98. Californium (Cf) - 251 g/mol
99. Einsteinium (Es) - 252 g/mol
100. Fermium (Fm) - 257 g/mol
101. Mendelevium (Md) - 258 g/mol
102. Nobelium (No) - 259 g/mol
103. Lawrencium (Lr) - 262 g/mol
104. Rutherfordium (Rf) - 267 g/mol
105. Dubnium (Db) - 270 g/mol
106. Seaborgium (Sg) - 271 g/mol
107. Bohrium (Bh) - 270 g/mol
108. Hassium (Hs) - 277 g/mol
109. Meitnerium (Mt) - 276 g/mol
110. Darmstadtium (Ds) - 281 g/mol
111. Roentgenium (Rg) - 280 g/mol
112. Copernicium (Cn) - 285 g/mol
113. Nihonium (Nh) - 286 g/mol
114. Flerovium (Fl) - 289 g/mol
115. Moscovium (Mc) - 288 g/mol
116. Livermorium (Lv) - 293 g/mol
117. Tennessine (Ts) - 294 g/mol
118. Oganesson (Og) - 294 g/mol

Molar Masses for 1-118 elements It Sticks!
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